How much CO2 is produced on burning 1 liter of fuel?

Answer 1

Well you don't state temp or pressure, so we can only assume STP conditions. At STP 1 mole will = 22.4 litres. Therefore there will be 0.044643 moles (1/22.4) here. This is multiplied by 44 (molecular weight of CO2) to give 1.9643 grams

Answer 2

Each liter of gasoline produces 1.7 kg (3.7 lbs) of CO2. There are about 509 liters per kg of CO2, or 865 liters emitted by one liter of fuel.

Gas occupies much greater volume than liquid. Burning gas, however, combines it with atmospheric oxygen, increasing the volume more yet.

Answer 3

From the related question, I found this:

"According to the CRC Handbook of Chemistry and Physics, the density of dry air at 20 degrees C at 760 mm of Mercury (one atmosphere of pressure) is 1.204 milligrams per cubic centimeter. "

1 liter = 1000 mL = 1000 cm3

(1.204 mg / cm3 ) * 1000 cm3 = 1204 mg = 1.204 grams

Answer 4

Most fuels are hydrocarbons so the answer is dependent on the ratio of hydrogen to carbon in their composition. Assuming that the fuel weighs some 800 g per liter (like diesel or gasoline) and has a formula of CnHn+2 then the carbon dioxide produced per mole of fuel is the same as the number of moles as is present in the original compound. As CO2 is essentially three times as heavy per mole as C, then each gram of C (or fuel as the H's don't weigh much) creates 3 g of CO2. As 1 litre of fuel weighs 800g, the carbon dioxide created is about 2,400 g.

Answer 5

Assuming standard temperature and pressure then the ideal gas states V = n x R x T / P<br><br>Which in the case of CO2 = (1000/44) x 0.08205 x 273.15 / 1 = 509.4 liters

Answer 6

The weight of carbon depends on its temperature. At 53.73 degrees Fahrenheit, one liter of carbon dioxide will weigh 0.001977 kilograms.

Answer 7

Weight of one mole of carbon dioxide = 44g

one mole is 22.4 litres.

Therefore, weight of 22.4 litres is 44g

weight of 1litre is 44/22.4 =1.964g

Answer 8

at STP, 1kg of a gas occupies 22.4 litres

Answer 9

1000