There are 5 digits, and if none can be repeated then the first digit can be chosen in 5 ways, the second can be chosen in 4 ways and the third in 3.
5 x 4 x 3 = 60.
60
A number with more than one digits: that is, an integer greater than 9.
This is a question of permutations; the answer is equal to the factorial of 5 (number of digits) divided by the factorial of 3 (number used in each selection), written 5! / 3!. This equals 120 / 6, or 20 ways.
A three digit number can be chosen in 9*10*10 = 900ways No. of ways to choose a three digit number without 7 is 8*9*9 = 648 ways probability of picking a three digit number that includes atleast one digit that is 7 is 1- (648/900) = 252/900 = 7/25
Assuming that 2356 is a different number to 2365, then: 1st digit can be one of four digits (2356) For each of these 4 first digits, there are 3 of those digits, plus the zero, meaning 4 possible digits for the 2nd digit For each of those first two digits, there is a choice of 3 digits for the 3rd digit For each of those first 3 digits, there is a choice of 2 digits for the 4tj digit. Thus there are 4 x 4 x 3 x 2 = 96 different possible 4 digit numbers that do not stat with 0 FM the digits 02356.
120. There are 6 digits. If we pick the digits in order, there are 6 possible digits for the first digit 5 remaining digits for the second digit 4 remaining digits for the third digit. 6*5*4 = 120.
It is -987. The smallest positive 3-digit integer with unique digits is 102.
81
The answer is 9*9!/9*109 = 0.0003629 approx.
The answer is a negative or positive integer with one or two digits.
12
The least possible integer is -98765432. The least possible positive integer is 10234567.
First, separate the negative and positive integers (put them into two separate groups). If there is a zero, you can put it in its own group - or put it into the same group with the positive integers. Negative integers come first, then zero, then positive integers.For positive integers:An integer with less digits comes before an integer with more digits.For integers with the same number of digits, look at the first digit. The integer with the smaller digit in this position comes first.If the first digit is the same, look at the second digit. If those are equal, look at the third digit, etc.For negative integers, it is the other way round - for example, an integer with MORE digits comes first.
9*9*9 = 729 ways.
Let me first re-phrase your question: What is the number of (positive) integers less than 10000 (5 digits) and greater than 999 (3 digits)? The greatest 4 digit integer would be 9999. The greatest 3 digit integer would be 999. Let's do some subtraction: 9999 - 999 = 9000 This works because as we count up from 999, each positive integer encountered satisfies your requirements until reaching 10000.
Six. 1551 2442 3333 4224 5115 6006
1
Positive integers are greater than negative integers. For positive integers: * The integer with more digits is larger. * If two integers have the same length, compare the first digit. If the first digit is the same, compare the second digit, then the third, etc., until you find a difference. In each case, the integer with the larger digit (at the first position where you find a difference) is the larger one.