answersLogoWhite

0


Best Answer

694 mL of glucose solution 0,2 M are needed.

User Avatar

Wiki User

7y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

7y ago

moles glucose needed = 25.0 g x 1mol/186 g = 0.139 moles
voluem of 0.2 M needed: (x L)(0.2 mol/L) = 0.139 moles
x = 0.694 L = 694 mls

This answer is:
User Avatar

User Avatar

Wiki User

8y ago

30 ml 50% dextrose + 70 ml water

This answer is:
User Avatar

User Avatar

Wiki User

10y ago

25

This answer is:
User Avatar

User Avatar

Anonymous

Lvl 1
3y ago

25

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many ml of 50 percent dextrose solution are needed to obtain 25 g of dextrose?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution How much of the 20 percent solution did the pharmacist use in the mixture?

A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution. How much of the 20 percent solution did the pharmacist use in the mixture (in liters).


Pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution How much of the 20 percent solution did the pharmacist use in the mixture?

10


How much of an 18 percent solution of sulfuric acid should be added to 360 ml of a 10 percent solution to obtain a 15 percent solution?

600ml.


How many gallons of a 9 percent salt solution must be mixed with 25 gallons of a 31 percent solution to obtain a 20 percent solution?

25 gallons


How many liters of a 20 percent solution of acid should be added to 10 liters of a 30 percent solution of acid to obtain a 25 percent solution?

10 liters.


50 percent dextrose solution and you need a 1 percent dextrose soultion. How do you figure that out?

If the percents given are by weight or mass, this is very straightforward: The ratio between the desired percentage and the initial percentage is 1/50. Therefore, a given mass of initial solution must be diluted to 50 times its original mass to obtain the desired lower concentration, or in other words, 49 parts of diluent must be mixed with each part of initial solution. If the percents involve volume measurements, it would be necessary to take into account and change in density occasioned by the dilution.


How much water must be added to 12 L of a 40 percent solution of alcohol to obtain a 30 percent solution?

4 litres


How many gallons of 3 percent salt solution must be mixed with 50 gallons of 7 percent salt solution to obtain a 5 percent salt solution?

50 gallons @ 3% must be added.


How many grams of sugar must be added to 60 grams of a solution that is 32 percent sugar to obtain a solution that is 50 percent sugar?

40.8 grams


How many qt of pure antifreeze must be added to 3 qt of a 10 percent antifreeze solution obtain a 20 percent antifreeze solution?

0.6 of a pint.


How much of water should be add to obtain a solution that is twenty percent antifreeze?

80% water


How many milliliters of 11.4M HCl solution are needed to obtain 0.260mol of HCl?

28 milliliters