# How many ml of 50 percent dextrose solution and how many ml of water are needed to prepare 100ml of 15 percent dextrose solution?

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30 ml 50% dextrose + 70 ml water
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# How many mg per ml in a twenty percent solution?

a 2.5% solution has 25mg per ml, therefore a 20% solution has 200mg per ml.

# How many ml of 25percent dextrose and needed to prepare 500 ml of 40percent dextrose if you are to make 40percent dextrose from 25percent dextrose and 60percent dextrose?

My calulation says 286ml of 25% and 214ml of 60%. 286 x .25= 71.50. 214 x .60= 128.40. 250 x .20= 50.00. 250 x .60= 150.00

# If an iv solution contains 5 percent wv of dextrose how many mg of dextrose is added by intravenous injection of 475 ml of this solution?

23.75 mg of Dextrose is added by intravenous injection of 475 ml of this solution .. wrong! . 5% WV means 5 grams/100ml ; therefore 23.75 grams/475ml; since there's 1000mg/g

# How many grams of glucose are needed to prepare 400 ml of a 2.0 percent glucose solution?

8.0 g according to my teacher but i dont know the formula

# How many grams of sodium chloride are needed to prepare 600 ml of a 0.9 percent saline solution?

600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl

# What is the composition of 5 percent dextrose solution?

what is the composition of dextrose 5%

143

# What solution is the 5 percent Dextrose in Lactated Ringer's?

Dextrose is a synonym of D-glucose (also known as grape sugar, corn sugar, and when it's present in blood, blood sugar).In 2013, Dextrose 5 percent in lactated Ringer's inject

# How do you prepare a 100ml solution from 1000 micrograms per ml?

So you have to have a milligram for every millilitre.But you have 100ml. Therefore you have to multiply 1mg by 100, toget 100mg. Weigh out 100mg or 0.1g and dissolve it to 100

280 grams.

# What is the number of Grams of 5.5 percent dextrose in a 1L solution of water?

55 gm in 1 L (a 1% solution is 1 gm/100ml)

# 50 percent dextrose solution and you need a 1 percent dextrose soultion. How do you figure that out?

If the percents given are by weight or mass, this is very straightforward: The ratio between the desired percentage and the initial percentage is 1/50. Therefore, a given mass

5% in pure water

# How do you prepare 200 ml of 1.25 percent NaoH solution?

25 mL of 10% NaOH + 175 mL of distilled water

# How many mL of a 20 percent solution are needed to prepare 500 mL of a 5 percent solution?

125 ml 500(ml) * 0.05 = 25 25 / 0.20 = 125
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2g?

# How many ml should be added to 100ml of a 25 percent solution to get produce a 20 percent solution?

add 25ml more of solution x * 20 = 100 * 25 x = 25