The number of orbitals in a given shell fit the equation 2(L)+1, where L=the angular quantum number.
L=0 corresponds with the s orbital, L=1 with p orbital, L=2 with d orbital, L=3 with f orbital, L=4 with g orbital, and L=5 with h orbital.
Therefore, we use 5 for L in the original equation and we see that there are 2(5)+1 or 11 possible h orbitals in a closed shell.
9
There are 36 types of orbitals in the sixth shell.
Krypton is a noble gas and hence has stable electronic configuration. Its valence shell configuration is 4s2 4p6 . Therefore, it has 1-s and 3-p full orbitals in its valence shell.
Always three!
If the question is an attempt to ask "How many orbitals are there with principal quantum number n = 2", then 4 orbitals which can hold a total of 8 electrons.
The 3rd shell can contain 18 electrons. The elements that have a 3rd shell as the outer shell are the the elements in period 3, where the 3s and 3p orbitals are filled to a maximum of 8 electrons. The 3d orbitals are filled in the 4th period in the transition elements.
There are three p orbitals in all levels 2 and above. these are the px, py and pz orbitals, the (suffix is the direction - px lies along the x axis). In the 5th level they will be 5px, 5py, 5pz
There are 5 d orbitals in a given sublevel.
Only four in each have been observed.
5 electrons in p orbitals in the outer shell. Cl has an electronic configuration of [Ne] 3s2, 3p5 In level 2 there a further 6 electrons in p orbitals making 11 electrons in total occupying p orbitals
3 shells; 2 electrons in the first shell, 8 in the second shell and 8 in the third shell.
9. The number of orbitals in a given shell fit the equation 2(L)+1, where L=the angular quantum number. L=0 corresponds with the s orbital, L=1 with p orbital, L=2 with d orbital, L=3 with f orbital, L=4 with g orbital, and L=5 with h orbital.