600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl
256 liters
Take 5 grams of calcium chloride and dissolve it in 100ml of solution to get a 5% solution of calcium chloride. The standard way to make a weight-volume solution is to take grams of the dry substance in 100ml of volume.
12ml
1.17 grams :)
100ml is 0.1 litres, so you need 0.1 moles of sodium chloride.
25
The volume is 0,3 mL.
125 ml 500(ml) * 0.05 = 25 25 / 0.20 = 125
300 ml
500ml = 500cm3 = 0.5dm3 0.250M = 0.250mol/dm3 number of moles = molarity x volume number of moles = 0.250mol/dm3 x 0.5dm3 = 0.125mol 0.125mol of NaCl is needed to prepare the required solution.
Sodium chloride may be used as standard (for example to prepare sodium solutions with known concentration) because is a stable compound.
In this instance, 50 mol of sodium chloride is needed and molar mass of NaCl is 58.5 g/mol. Hence the mass we need is 29250 g. But this amount of salt could not be dissolved in 500 ml of water, so we cannot prepare this solution practically.
90 ml of dextrose and 4.41 litres of water.
150 mL x 40.0 g LiNO3/100 mL solution = 60.g of solute
Sodium chloride is needed to precipitate soap from solutions.
Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.
25 mL