1 acre = 43,560 square feet
1 cubic foot = 1,728 cubic inches
1 gallon = 231 cubic inches
Volume of the lake = (1.5 x 43,560) x (5) = 326,700 cubic feet = 2,443,885.7 gallons (rounded)
how many gallons of water does a swimming pool 15 feet by 4 feet deep hold
It is 0.1388... recurring acres.
587.5 US gallons Volume of a cylinder = PI * height * radius * radius 3.14159 * 4 * 2.5 * 2.5 = 78.5398 cubic feet 78.5398 (cubic feet) = 587.5185 US gallons
The volume is (16' x 32' x 7') = 3,584 cubic feet = 26,810.18 gallons (rounded)We have no way of knowing how much water is in it.It might even be empty.
5000 x 1/12 = 416.67 cubic feet At 7.48 gallons per cubic foot, that is 7.48 x 416.67 = 3117 gallons
A 25-acre pond that is uniformly 6 feet deep will hold about 48,877,714 gallons of water.
In order to cover 7,000 acres 183.5-ft deep, you'll need . . .-- 0.38012 cubic mile-- 55,952,820,000 cubic feet-- 418,556,160,000 gallons-- 96,686,472,960,000 cubic inches
If the pond is uniformly 6-feet deep it would contain about 1,955,109 gallons of water.
I'm assuming you mean acre feet of water. If that is the case, then there are 325,850.58 gallons in one acre foot of water or 4,887,758.7 gallons of water in 15 acre feet of water.
how many gallons of water does a swimming pool 15 feet by 4 feet deep hold
17,953.2 gallons
250 ft3 = 1870.13 US gallons
6,200 gallons.
3,398.4 gallons.
5,974 gallons.
1,770 gallons.
24,685.79 gallons