0
How many even 3-digit numbers can be formed from digits 1 3 5 and 7 if each digit can be used more than once?
Wiki User
∙ 12y ago
If your only option is to assemble the digits into a single number, then the answer is 0, as you need at least one even digit to make an even number, and the digits provided are all odd ones.
If on the other hand, you can use operators on them (e.g. 1 + 3 + 5 + 7), then you actually have quite a large number of possibilities. For example:
1 + 3 + 5 + 7
- 1 + 3 + 5 + 7
1 - 3 + 5 + 7
(1 + 3) / ( 7 - 5)
1 + √(7 + 5 - 3)
31 + 57
etc. etc.
Alternatively, if you're not worried about them being even numbers, then the answer is 24.
Wiki User
∙ 12y ago
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27 three digit numbers from the digits 3, 5, 7 including repetitions.
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500
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840
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1 set
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