Yes. Power(P)=Current(I)xVoltage(E) or P=I x E, and since in a series circuit current is constant and voltage is additive then:
P(series)=Pr1+Pr2+Pr3........ Actually, power dissipated in series circuits is P = I^2 * R and in parallel power dissipated = V^2/R
The total resistance in a series connection is equal to SUMof the individual resistanceSay you want to measure the voltage across the series of these two resistors:
--- R1 --- R2 ---
Current I is the same in the two resistors. If you write 2nd kirchhoff's law, you get that the total voltage V is equal to VR1 + VR2.
For each resistor "k" you have VRk= Rk IRk.
By substitution, you have V = VR1 + VR2 = R1 I + R2 I = (R1 + R2) I = Req I
So, in the end, Req = R1 + R2
For resistors in a series (connected end to end), the resistances simply add together.
If the resistors are in parallel (side by side), things are a bit more complex: take the inverse of each resistance ( 1 / resistance ), and add them together; then take the inverse of the result. This looks like: 1 / ( 1/R1 + 1/R2 + ... + 1/Rn ).
If the arrangement is more complex than simple series or parallel resistances, then working out the resistances involves setting up and solving a system of linear equations.
In a series circuit the current is the same in each resistor. The voltage across each resistor will be the current multiplied by the resistance.
The setup isn't quite clear. I'll assume you have two or more resistors in series, and in parallel. In parallel, each resistor gets the full voltage. For example, if the power source provides 10 V, each resistor gets 10 V. In series, each resistor gets only part of the voltage. For example, in the case of two identical resistors in series, each will get 5 V. As a result, less power will be dissipated. Exactly how much less will depend on how many resistors are used, and on the specific resistance values; you can calculate the power dissipated in specific cases with the formula P = V2/R, or P = I2R. Check the Wikipedia article on "Voltage divider", on how to calculate the voltage for individual resistors.
Yes, Voltage in series is additive. Formula Eapp=Er1+Er2+Er3..... -Kirchoffs Voltage Law: the sum of all voltage drops must equal the source voltage
When connected in series, the overall effective resistance of a bunch of individual resistors is the sum of the individual resistances. It's always more than the resistance of any individual. When connected in parallel, the reciprocal of the overall resistance of a bunch of individual resistors is the sum of the reciprocals of the individual resistances. It's always less than the resistance of any individual. When two resistors are connected in parallel, the overall effective resistance of the pair is (the product of the two individual resistances) divided by (the sum of the two individual resistances). It's always less than the smaller individual resistance.
I observe that the total effective resistance of several resistors in series is the sum of the individual resistance values of the individual resistors.
The total resistance in a series circuit is determined by adding (summing) the individual resistances of each component in the circuit.
86k. Resistance in series is the sum of the individual resistors.
There is no such thing as a "parallel series". The total effective resistance of many resistors in series is the sum of the individual resistances. It's more than the greatest individual. The total effective resistance of many resistors in parallel is the reciprocal of the sum of the individual resistances' reciprocals. It's less than the smallest individual.
The resistance of two or more resistors connected in series is the sum of the individual resistances. (If any of the connections between them is sloppy and involves some resistance at the connection, then that also has to be added in.)
When connected in series, the overall effective resistance of a bunch of individual resistors is the sum of the individual resistances. It's always more than the resistance of any individual. When connected in parallel, the reciprocal of the overall resistance of a bunch of individual resistors is the sum of the reciprocals of the individual resistances. It's always less than the resistance of any individual. When two resistors are connected in parallel, the overall effective resistance of the pair is (the product of the two individual resistances) divided by (the sum of the two individual resistances). It's always less than the smaller individual resistance.
The resistance of a series circuit is simply the sum of the individual resistors.
I observe that the total effective resistance of several resistors in series is the sum of the individual resistance values of the individual resistors.
Add all the individual resistance values.
The total resistance in a series circuit is determined by adding (summing) the individual resistances of each component in the circuit.
86k. Resistance in series is the sum of the individual resistors.
1.In series connection the total resistance is equal the total number of resistor that was connected in series 2.the current is constant in a series connection 3.in a series connection total voltage is equal the number of of volt per cells
The effective resistance of several resistors in series is the sum of the individual resistances.
There is no such thing as a "parallel series". The total effective resistance of many resistors in series is the sum of the individual resistances. It's more than the greatest individual. The total effective resistance of many resistors in parallel is the reciprocal of the sum of the individual resistances' reciprocals. It's less than the smallest individual.
When many resistances are connected in series, the equivalent resistance is greater than the greatest single resistance. When many resistances are connected in parallel, the equivalent resistance is less than the smallest single resistance.
Three 8.0-W resistors are connected in parallel. What is their equivalent resistance?