At half titration pH=pKa (you need the pH from the graph of your titration, y axis)
ph = pKa + log (base/acid)
10^-pKa = Ka
Kw=Ka*Kb
Kb=Kw/Ka
Ka = Kw/Kb
It should take just exactly twice the volume to reach the balance point.
Assuming you know how to find the equivalence point on the titration curve, and assuming it is not [strong acid/strong base] or [weak acid/weak base], all you need to do is find the half equivalence point, which gives you the pKa of the first solution. Then to get the Ka, you go 10-pKa .
half change
AmmoniA is soluble in water. Ammonium is a polyatomic ion and can only exist as the positive HALF of a compound, not independently.
i think ...one donate the electrons and other accept the electrons i.e one oxidized and other reduced. Raman sir what ever the defination ap jo diye na ,vo mujae half answer jise dikra hy, what v have learnt abt redox titration is all abt oxidation and reduction. In simple words " the principle involved in redox titration is accepting the electrons or donating the electrons simultaneously donating hydrogens or accepting the hydrogens."
It should take just exactly twice the volume to reach the balance point.
Assuming you know how to find the equivalence point on the titration curve, and assuming it is not [strong acid/strong base] or [weak acid/weak base], all you need to do is find the half equivalence point, which gives you the pKa of the first solution. Then to get the Ka, you go 10-pKa .
At 'half way' point the pH is equal to the pKa value of the acid: pH = pKa - log[cA/cB] because at that point cA = cB . So pH = pKa = - log(5.2*10-6) = 5.3
Equivalence point is reached when Reactants react at Stoichiometric ratios and reach the Endpoint so that no more of the solution being titrated is found.Eg: Strong base + Strong Acid: HCL+NaOH--> NaCl+H2O1mol of Hcl Requires 1 mol of NaCl,Therefore 3.65 moles of Hcl Requires 3.65Moles of NaOH and equivalence point is reached when that much is added to the acid being titrated for example .Half Eq point is when Half of the Solution being titrated has reacted. It is a point on a titration curve which corresponds to the addition of exactly half of the volume of the titrant needed to reach equivalence point (or end point )Corrected:So, at HALF-WAY Eq. point the pH = pKa, since the actual concentration of ACID is equal to concentration of its conjugate BASE because both are equal to HALF of the original (unknown) acid concentration to be titrated (half left = half formed).
half change
.5 a half is a half no matter what it is half of
Yes, there is a small amount of ammonia in the air, caused by natural breakdown processes. The average amount of ammonia is less than 0.5 ppmv but his value may be significantly higher downwind of agricultural operations such as chick farms which generate ammonia from the collected manure. In general ammonia has a short half life in the atmosphere as it is washed out by rain and absorbed onto damp surfaces.
The -3dB point is the point of half power. In a filter, the -3dB point, more commonly called the half-power point, is the point where the output power is one half the input power. A bandpass filter has two half-power points, and the distance between them is called the bandwidth, whereas a low-pass or high-pass filter has one half-power point, which is called the cutoff frequency. In terms of voltage, the half-power point is where the voltage is 0.707 (1 / square root(2)) of the input voltage.
When producing ammonia, there is not a 100% change from reactants into products. In fact, around half of the reactants will change into ammonia, and then equilibria is reached and the amount of ammonia will stay the same. Increasing the pressure shifts the equilibria, so that more ammonia is produced when an equilibria is reached, making the process more efficient. Hypothetical example: 1 litre of reactants (normal pressure) -----> 0.5 litre reactants and 0.5 litre ammonia 1 litre of reactants (high pressure) -------> 0.2 litre reactants and 0.8 litre ammonia
it is the point where something is "cut in half." So if we bisect a line, we cut it in half and the midpoint is the bisection point. That is just one example
Cordova is the half point. Highway is I40W
Each mole of ammonia requires one mole of nitrogen atoms. However, the nitrogen in the air occurs as diatomic molecules; therefore, only one-half mole of molecular nitrogen is required for each mole of ammonia.