Write a program in assembly language to add two 8 bit numbers?

Answer 1

we can do this using two techniques:

here i m assuming that two number which is to be multiplied are given..

say 05H and 04H,

so coz 5*4 = 5+5+5+5 = 20

and 4*5 = 4+4+4+4+4 = 20

use this concept ...

MVI A,05H;

MVI B,04H;

L1:

ADD A;

DCR B;

JNZ : L1;

STA 2004H;

HLTType your answer here...

Answer 2

;this program adds 2 1-digit numbers
;without carry ,sum < 10 or with carry , sum >9
;coded by -----LenmorVash------
;coded in emu8086




org 100h


mov dx,offset str
mov ah, 09h
int 21h


mov dx,offset str2
mov ah, 09h
int 21h


mov dx,offset str3
mov ah, 09h
int 21h


;---new line---


mov ah, 2
mov dl, 10
int 21h
mov ah, 2
mov dl, 13
int 21h
;---------------
;========================================
mov dx,offset str5
mov ah, 09h
int 21h


;accept 1 char from keyboard
mov ah, 1
int 21h




;convert to number
sub al,30h


mov [temp],al


;=======================================





;---------------------------------------


mov dx,offset str6
mov ah, 09h
int 21h


;accept 1 char from keyboard
mov ah, 1
int 21h




;convert to number
sub al,30h


mov [temp2],al




;-----------------------------------------






;++++++++++++++++++++++++++++++++++++++++++
;ADD [temp],[temp2] xxx illegal xxx


mov bh, [temp]
add bh, [temp2]





;jump to g10 if sum is greater than 9, >=10
cmp bh,09h
jg g10




;sub bh,30h
;sub bl,30h


;push bx








;print answer if not greater than 9


add bh, 30h ;convert back to ASCII equiv


mov dx,offset str7 ;some message
mov ah, 09h
int 21h


mov ah,2 ;print answer
mov dl,bh
;mov dl,ch
;add dl, 30h
int 21h




jmp exit ;jump to program termination


;---------------------------------------

;execution jumps here if answer >=10
g10:



xor ax,ax ;clear ax to 00, ah=0h al=0h


mov al, bh ;transfer prev. answer to al


aaa ;separate result to AH and AL, and correct the
;sum using AAA



mov cx,ax ;transfer AX to CX



add cx, 3030h ;convert back to ASCII equiv





mov dx,offset str7 ;some message
mov ah, 09h
int 21h


mov ah,2 ;print answer


mov dl,ch ;1st digit in CH
int 21h






mov dl,cl ;2nd digit in CL
int 21h






;++++++++++++++++++++++++++++++++++++++++++




exit:





;pause.......
mov ah,00h
int 16h
;............


ret






str db "Lab. Activity No.2 $"
str2 db 10,13,"Codere: Lenmor Vash $"
str3 db 10,13,"God Bless ^_^ $"


temp db 0
temp2 db 0




str5 db "Enter the 1st No: $"
str6 db 10,13,"Enter the 2nd No: $"


str7 db 10,13,"The answer is: $"

Answer 3

This depends very much on which type of assembly language you are using.

Typically one uses a compare instruction if it exists, or a subtract instruction followed by checking a condition flag (e.g. carry, borrow, negative, etc.). Note that it is important to distinguish between a compare of signed vs. unsigned integers, as the results will differ when the two arguments have opposite high order bits.