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How do you solve the quadratic equation t2-4t equals 21 by factoring?
Wiki User
∙ 14y ago
I suppose you mean t2-4t=21
- minus 21 from both sides
- we get-> t2-4t-21=0
- find 2 numbers that multiply to get 21, and combined each other to get 4.
- 3&7 work, 3*7=21, 3-7=-4
- --> (t-7)(t+3)=0
- Ex: X*Y=0, that can be mean X or Y =0, or X andY=0
- Our equation (t-7)(t+3)=0, means that t-7=0.......t+3=0
- t-7=0------->t=7
- t+3=0------->t=-3
- *Remember* Quadratic equation mostly has two answers.
Wiki User
∙ 14y ago
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