40 grams, this is the 1M NaOH standard laboratory solution.
to prepare 1N we have to dilute 40gms of NaOH in 1 litre of water as for NaOH normality =molarity so to prepare 0.1N NaOH we have to dilute 4gms of NaOH in 1 litre of water..
we need 0.8gm NaoH and dissolved in 10 ml of water to make 2N solution of NaoH .
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
"Dilute NaOH" without any other specifications in a chemistry lab generally refers to a 6M solution of NaOH in water.
40 grams, this is the 1M NaOH standard laboratory solution.
to prepare 1N we have to dilute 40gms of NaOH in 1 litre of water as for NaOH normality =molarity so to prepare 0.1N NaOH we have to dilute 4gms of NaOH in 1 litre of water..
we need 0.8gm NaoH and dissolved in 10 ml of water to make 2N solution of NaoH .
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
"Dilute NaOH" without any other specifications in a chemistry lab generally refers to a 6M solution of NaOH in water.
You need 2,4 g NaOH (0,06 moles).
Dissolve slowly 50 g NaOH in 100 mL water; advertisement: sodium hydroxide solution is dangerous !
dissolve 100g in 300ml water
4 moles or 160 g NaOH is required for one litre solution.
Dissolve 0.4 g of NaOH in 100 ml of water. Try it out. Actually it is not suitable to prepare NaOH solutions in standard flasks.It should be made in beakers & must be standardised..This is done to find the correct normality...
MaVa=MbVb (6.0M NaOH)(x)=(0.10M solution)(1.0L) x=0.017L of 6.0M NaOH Convert to mL (1000mL in 1L) 17mL of 6.0M NaOH
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.