With an instrument called a multimeter. The single meter incorporates within it a volt meter, an ohm meter and an amp meter. For higher amperages a clamp on amp meter is recommended as the circuit does not have to be opened to take a reading.
Assuming a pure resistive load. Watts = Amps x Volts therefore Volts = Watts / Amps Volts = Amps x Resistance therefore Resistance = Volts / Amps Therefore, Resistance = (Watts / Amps) / Amps and simplified that means Resistance = Watts / ( Amps x Amps)
If it's a straight DC circuit, then by solving Ohm's law.
Resistance = Volts divided by Amps.
In an AC circuit, it may not be possible. You can still use Ohm's law, but it's technically impedance rather than resistance that you calculate.
amps is current
watts is power
volts is voltage
PIV
P=IV
So if you rearrange this to work out the current you have to do power divided by voltage.
Divide the watts by the volts
Watts = Volts x Amps
Amps = Watts / Volts
Volts = Watts / Amps
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The equation that you are looking for is I = W/E, Amps = Watts/Volts.
I=V/R
I=amp
v= volts
R= resistance
pretty simple just divide the volt by the resistance
The equation that you are looking for is R = E/I. Resistance = Volts/Amps.
Divide...
The values you state are two different values. KVA is the value of voltage times amperage times 1000. The voltage value of 240 volts is just 240 volts. If you have an amperage it can be applied to the first equation to find the KVA value.
To calculate the amperage of an appliance use the following equation, I = W/E. Amps = Watts/Volts. In North America the home voltage for larger appliances is 240 volts. Somewhere in the oven there will be a name plate. on it will give you the wattage of the device. Divide the voltage of 240 volts into this wattage value and you will end up with the amperage that the oven requires to operate.
You can't convert volts to amperes. Those are quite different units; that would be like converting, say, meters to seconds.
To answer this you have to know how many volts will be used. If you know the voltage then you can calculate the current by dividing voltage into wattage. For example; an electric heater rated at 700 watts when plugged into a 115 v outlet will draw 700/115 = 6.08 amps of current.
Amps are coulombs per second, and there is no information on rates given here.
Divide...
Wire is sized by the amperage that it will carry. 5 kW is 5000 watts. The equation to find watts is W = Amps x Volts. The equation to find amps is Amps = Watts/Volts. As you can see a voltage is needed to calculate the amperage. Once the amperage is stated, the wire size can be given for that particular amperage.
Divide the circuits amperage into the volt amps and you will get the voltage.
Watts is the product of amps x volts. To give an answer the amperage needs to be given.
volts divided by resistance equals maximum amperage (current)
Amps = Watts / (Volts x Power Factor). The Power Factor is one for resistive loads and decreases for inductive loads like motors.
The values you state are two different values. KVA is the value of voltage times amperage times 1000. The voltage value of 240 volts is just 240 volts. If you have an amperage it can be applied to the first equation to find the KVA value.
To calculate the amperage of an appliance use the following equation, I = W/E. Amps = Watts/Volts. In North America the home voltage for larger appliances is 240 volts. Somewhere in the oven there will be a name plate. on it will give you the wattage of the device. Divide the voltage of 240 volts into this wattage value and you will end up with the amperage that the oven requires to operate.
You can't convert volts to amperes. Those are quite different units; that would be like converting, say, meters to seconds.
the answer is dc volts are rectified from ac volts and the amperage will be the same unless you account for the slight drop from the rectifier. dc volts from a battery have no relationship to ac volts. you can derive ac volts from a dc source using an inverter.
Yes, two values are used, amperage and voltage. The product of amps times volts is watts. It is the amount of kilowatt per hour used that the utility bill is based upon.