0
How do you find the equation of the perpendicular line bisecting the line segment of -2 5 and -8 -3?
Wiki User
∙ 13y ago
if u don't now then i don't now
Improved answer as follows:-
First find the mid-point of (-2, 5) and (-8, -3) which is (-5, 1)
Then find the slope or gradient of (-2, 5) and (-8, -5) which is 4/3
The perpendicular slope is the negative reciprocal of 4/3 which is -3/4
So the perpendicular bisector passes through (-5, 1) and has a slope of -3/4
Use y -y1 = m(x -x1)
y -1 = -3/4(x- -5)
y = -3/4x-11/4 which can expressed in the form of 3x+4y+11 = 0
So the equation of the perpendicular bisector is: 3x+4y+11 = 0
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
To find a segment parallel to another segment and through a given point using paper folding techniques requires two steps The first step is to find a line perpendicular to the given segment and passi?
true
To find a segment perpendicular to a given segment and through a given point fold a piece of paper so that the fold goes through the point and the pieces of the segment on either side of the fold matc?
TRUE
If segment AD perpendicular segment CE m angle 1 m angle 6 and m angle 1 37 find m angle GMD?
143
Find the equation of a straight line perpendicular to the line 4y-3x12?
There are infinitely many lines perpendicular to this line. All of them have the slope of -4/3, if that fact is of any help to you.
How do you form an equation for the perpendicular bisector of the line segment joining the points of p q and 7p 3q showing all details of your work?
First find the midpoint the slope and the perpendicular slope of the points of (p, q) and (7p, 3q) Midpoint = (7p+p)/2 and (3q+q)/2 = (4p, 2q) Slope = (3q-q)/(7p-p) = 2q/6p = q/3p Slope of the perpendicular is the negative reciprocal of q/3p which is -3p/q From the above information form an equation for the perpendicular bisector using the straight line formula of y-y1 = m(x-x1) y-2q = -3p/q(x-4p) y-2q = -3px/q+12p2/q y = -3px/q+12p2/q+2q Multiply all terms by q and the perpendicular bisector equation can then be expressed in the form of:- 3px+qy-12p2-2q2 = 0
How do you find the midpoint the slope the perpendicular slope and the equation for the perpendicular bisector of the line segment joining the points of 3 5 and 7 7?
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
How do you work out and find the perpendicular bisector equation meeting the straight line segment of p q and 7p 3q?
First find the mid-point of the line segment which will be the point of intersection of the perpendicular bisector. Then find the slope or gradient of the line segment whose negative reciprocal will be the perpendicular bisector's slope or gradient. Then use y -y1 = m(x -x1) to find the equation of the perpendicular bisector. Mid-point: (7p+p)/2 and (3q+q)/2 = (4p, 2q) Slope or gradient: 3q-q/7p-p = 2q/6p = q/3p Slope of perpendicular bisector: -3p/q Equation: y -2q = -3p/q(x -4p) y = -3px/q+12p2/q+2q Multiply all terms by q to eliminate the fractions: qy = -3px+12p2+2q2 Which can be expressed in the form of: 3px+qy-12p2-2q2 = 0
How do you work out an equation for the perpendicular bisector of the line segment AB when A is at -4 8 and B is at 0 -2?
First find the midpoint of the line segment AB which is: (-2, 3) Then find the slope of AB which is: -5/2 The slope of the perpendicular bisector is the positive reciprocal of -5/2 which is 2/5 Then by using the straight line formula of y-y1 = m(x-x1) form an equation for the perpendicular bisector which works out as:- y-3 = 2/5(x-(-2)) y = 2/5x+4/5+3 y = 2/5x+19/5 => 5y = 2x+19 So the equation for the perpendicular bisector can be expressed in the form of:- 2x-5y+19 = 0
To find the distance from a point C to the line AB you must find the length of the segment from C to AB?
perpendicular
To find a segment parallel to another segment and through a given point using paper folding techniques requires two steps The first step is to find a line perpendicular to the given segment and passi?
true
To find a perpendicular line segment from a point to a line fold the paper that the two endpoints of the segment match up?
False... good luck with Apex :)
Can You can find a perpendicular line segment from a point to a line using the folding paper technique?
Yes, I can.
To find a segment perpendicular to a given segment and through a given point fold a piece of paper so that the fold goes through the point and the pieces of the segment on either side of the fold....?
True
To find the midpoint of a segment first mark a point not on the segment then fold the paper so that the point you marked and a point on the line are included in the fold true or false?
False that is to find the perpendicular bisect.
To find a segment perpendicular to a given segment and through a given point fold a piece of paper so that the fold goes through the point and the pieces of the segment on either side of the fold matc?
TRUE
To find a segment perpendicular to a given segment and through a given point fold a piece of paper so that the fold goes through the point and the pieces of the segment on either side of the fold m?
True.......................Apexvs
If segment AD perpendicular segment CE m angle 1 m angle 6 and m angle 1 37 find m angle GMD?
143
