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this time is basically the instant when an object has a particular velocity(instantaneous velocity). so on the graph draw a line from the particular value of the velocity and then draw a vertical line on time axis to find the time for that velocity.
Wiki User
∙ 14y ago
Wiki User
∙ 12y agoJust by drawing a tangent to the curve at a given point and finding its slope we can find the acceleration at that instant.
Wiki User
∙ 11y agoDisplacement is the area under the velocity-time graph. Refer to the related links for more information.
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How do you go from a position graph to a velocity graph?
you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.
Calculate distance from a velocity time graph?
The area between the graph and the x-axis is the distance moved. If the velocity is constant the v vs t graph is a straight horizontal line. The shape of the area under the graph is a rectangle. For constant velocity, distance = V * time. Time is the x-axis and velocity is the y-axis. If the object is accelerating, the velocity is increasing at a constant rate. The graph is a line whose slope equals the acceleration. The shape of the graph is a triangle. The area under the graph is ½ * base * height. The base is time, and the height is the velocity. If the initial velocity is 0, the average velocity is final velocity ÷ 2. Distance = average velocity * time. Distance = (final velocity ÷ 2) * time, time is on the x-axis, and velocity is on the y-axis. (final velocity ÷ 2) * time = ½ time * final velocity ...½ base * height = ½ time * final velocity Area under graph = distance moved Most velocity graphs are horizontal lines or sloping lines.
How do you develop the general velocity equation from a Velocity vs Time graph?
Derivitives of a velocity : time graph are acceleration and distance travelled. Acceleration = velocity change / time ( slope of the graph ) a = (v - u) / t Distance travelled = average velocity between two time values * time (area under the graph) s = ((v - u) / 2) * t
Can a position time graph be created from a velocity time graph?
Distance travelled from a velocity / time graph can be calculated from area under graph, say area under (v/t) graph from 0 - 1 seconds = distance travelled after 1 second, then do 0 - 2 seconds, 0 - 3 etc for set of data for distance / time graph
What does the slope of a time vs distance graph equal?
Slope of time Vs distance graph gives the inverse of velocity.
What is the difference between a velocity time graph and a position time graph?
Simply put, a velocity time graph is velocity (m/s) in the Y coordinate and time (s) in the X and a position time graph is distance (m) in the Y coordinate and time (s) in the X if you where to find the slope of a tangent on a distance time graph, it would give you the velocity whereas the slope on a velocity time graph would give you the acceleration.
How do you go from a position graph to a velocity graph?
you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.
What does a zero velocity graph look like?
In a velocity-time graph it will be the time axis (where velocity = 0). On a distance-time graph it will be a line parallel to the time axis: distance = some constant (which may be 0).
What does a distance time graph allow you to find?
Besides obviously distance at any instant, on a connected, continuous distance-time graph, you can obtain instantaneous velocity and instantaneous acceleration.
Calculate distance from a velocity time graph?
The area between the graph and the x-axis is the distance moved. If the velocity is constant the v vs t graph is a straight horizontal line. The shape of the area under the graph is a rectangle. For constant velocity, distance = V * time. Time is the x-axis and velocity is the y-axis. If the object is accelerating, the velocity is increasing at a constant rate. The graph is a line whose slope equals the acceleration. The shape of the graph is a triangle. The area under the graph is ½ * base * height. The base is time, and the height is the velocity. If the initial velocity is 0, the average velocity is final velocity ÷ 2. Distance = average velocity * time. Distance = (final velocity ÷ 2) * time, time is on the x-axis, and velocity is on the y-axis. (final velocity ÷ 2) * time = ½ time * final velocity ...½ base * height = ½ time * final velocity Area under graph = distance moved Most velocity graphs are horizontal lines or sloping lines.
In what kind of graph can you identify velocity?
A graph of distance against time.
How do you know there is no motion on a distance time-graph?
distance = velocity x time so on the graph velocity is slope. If slope is zero (horizontal line) there is no motion
Why is the distance time graph a straight line for?
A straight line on a distance - time graph represents a "constant velocity".
What is the quantity which is measured by the area occupied below the velocity - time graph?
Distance travelled (displacement). Distance = velocity/time, so velocity * time = distance. Likewise, x = dv/dt so the integral of velocity with respect to time (area under the graph) is x, the distance travelled.
How do you develop the general velocity equation from a Velocity vs Time graph?
Derivitives of a velocity : time graph are acceleration and distance travelled. Acceleration = velocity change / time ( slope of the graph ) a = (v - u) / t Distance travelled = average velocity between two time values * time (area under the graph) s = ((v - u) / 2) * t
The slope of a line on a distance time graph?
Velocity.
What does the area of a velocity time graph gives?
Distance.
