If you are referring to residential wiring, then refer to the appropriate tables in BS 7671:2008 Requirements for Electrical Installations (the IEE Wiring Regulations). It's too complicated to be answered in this forum and requires prerequesite knowledge you may not have.
If the voltage is supplying any current through the cable, i.e. if there is any 'load' at the end, then the voltage will drop through the cable.
It will decrease the voltage drop.
The voltage drop in a wire has nothing to do with the insulation. Voltage drop has to do with the cross sectional area of the wire.
cross sectional area of cable * voltage drop
Voltage drop depends on the size & length of the wire and the wattage of the bulbs. If they make an LED replacement bulb , you would hardly notice the voltage drop.
A: ANY CABLE will have a definite impedance and if current flow there is going to be a definite voltage drop because of it
The voltage drop depends on the current through the cable.For DC current in cable of 16 mm diameter, at 68° F, the voltage drop is(0.00857) x (current, Amperes) volts.
The formula for a simple DC voltage drop across a cable is:VDrop = Vmeasured at the input of cable - Vmeasured at the output of cableThis formula may seem simplistic however keep in mind that the sensitivity, accuracy and resolution of measuring instrument instrument is what is really important.If you know the DC current flowing through the cable and the impedance of the cable then you can use Ohm's law. Vdrop = I R where Vdrop is the voltage drop across the cable in volts I is the current flowing through the cable in amperes R is the resistance of the cable in ohms.ADDITIONALCalculation of the voltage drop is given by the formula belowVoltage Drop (Volt) = [(mV/Am)/1000] * I * lWhere mV/Am = millivolt drop per meter per ampere of the cable(this information is given in the table based on IEE Wiring Regulation)I = Current in the cable (in Ampere)l = Distance of cable (in Metre)See related links below
It is mandatory to use a larger wire size to overcome voltage drop at the load.
to calculate the cable size of a run of 30 meters long you first will have to know the current of the appliance use the voltage drop formula V d = (mVxIxL)/1000 once the voltage drop is less than 2.5% of the nominal voltage, the cable should be upsize.
The answer will depend on many factors such as:distance between the two points for which a voltage drop is to be calculated i.e the length of the cable runwire size and material (copper, aluminum...)type of insulation used in the cabletype of cable fixing (in the open air, along a wall, in a duct, underground, etc.)expected ambient temperature at full loadFor more information please see the Related Link and the answers to the Related Questions shown below.
This is a voltage drop question. The amperage of the circuit must be given. Without the load amperage this question can not be answered.