Your question is rather vague. Are you asking how do you determine the reactive power of a capacitor bank necessary to improve the power factor of a load (in which case, is it a single-phase or a three-phase load), or are you asking how to convert a capacitor bank's capacitance into reactive power?
If the former, then you need to know the reactive power of the load before power factor-improvement, and the resulting reactive power after power-factor improvement, and the difference between these two will tell you how much reactive power you need to add in the form of capacitors.
If that's really all you know, then you can't is the simple answer. Incidentally, the symbol for kilowatt is kW, not kw.
kvar = kva*sin@
kvar = kva*sin@
It depends on the power factor of the load, but for a load power factor of 0.7 on a 2000 kVA transformer the real power and reactive power are both 1400 kilo (watts and VAR). So a 1400 kVAR capacitor on the load would restore the power factor to 1, allowing 2000 kW to be drawn instead of only 1400 kW.
420 micro farad=1 kvar
A negative KVAR reading can be eliminated by adding an inductor to the circuit.
It depends upon at how much voltage level 400 kvar capacitor bank is used.
Generally the capacitor rating of a bank are decided on the load factor.ie higher the KVAR higher the capacity.KVAR is the reactive power in which load angle differs with the load variation.If we know load factor multiply it by the sine angle which gives us the capacity of the cpapcity of the load bank. Generally the capacitor rating of a bank are decided on the load factor.ie higher the KVAR higher the capacity.KVAR is the reactive power in which load angle differs with the load variation.If we know load factor multiply it by the sine angle which gives us the capacity of the cpapcity of the load bank. Generally the capacitor rating of a bank are decided on the load factor.ie higher the KVAR higher the capacity.KVAR is the reactive power in which load angle differs with the load variation.If we know load factor multiply it by the sine angle which gives us the capacity of the cpapcity of the load bank.
Cable sizing is based on amperage of the load. The rating of the capacitor bank and the voltage at which it operated need to be stated to give an answer.
{| |- | capacitance of the capacitor is mentioned in KVAR. Formula : KVAR = KW*tan@ FOR tan@, First note the power factor & KW without connecting capacitor. The noted power factor is in cos@.Convert the cos@ value in tan@. for ex. If power factor is 0.6, KW = 200 cos@ = 0.6 cos-1 (0.6) = 53.1 tan (53.1) = 1.333 200*1.333 = 266.6 KVAR if you use 266 KVAR capacitor, Then the power factor improves to unity (1.000). |}
we can use the Out Put Capacitor Ex Kvar
kvar = kva*sin@
kvar = kva*sin@
You end up with a leading power factor. The Kvar meter will run backwards.
Normal power is the multiplication of current to combination of resistive and reactive or capacitive load. From the vector sum of Apparent power minus real power we can get reactive power(KVAr), which is basically lagging power due to reactive load. This will be the exact rating of capacitor bank. You can find it by cos $ of apparent power.
kvar can be calculated as follows the a product KVA andt the sine of the angle between the KVA and KW.
for power factor correction kVAR for lasers Joules if you make them with capacitors and know the voltage and frequency you can figure either from microfarads energy =joules=kg-meters=watt -seconds= (C * e^2)/2 var = X(c) * e
It depends on the power factor of the load, but for a load power factor of 0.7 on a 2000 kVA transformer the real power and reactive power are both 1400 kilo (watts and VAR). So a 1400 kVAR capacitor on the load would restore the power factor to 1, allowing 2000 kW to be drawn instead of only 1400 kW.