In transcription, the mRNA strand is formed by complementary base pairing of the template DNA strand. However we should note that the nitrogenous bases in mRNA are Adenine, Guanine, Cytosine and Uracil, while those in DNA are Adenine, Guanine, Cytosine and Thymine.
So the mRNA strand would be formed by matching the A in DNA with U in mRNA, T in DNA with A in mRNA, C in DNA with G in mRNA and G in DNA with C in mRNA.
I hope that helps!
Suppose the DNA sequence for the first message in part B began with TGT CGA instead of TGA CGA. Would the message change ?
The HIV virus is an RNA virus, so you know the sequence AUCUU is the RNA sequence. (You also know it is RNA because it contains uracil.) HIV is a retrovirus, so its RNA will be transcribed to DNA by the enzyme reverse transcriptase and then inserted into the host's genome. The RNA sequence of AUCUU would be transcribed to TAGTT.
DNA sequences contain the nitrogen bases adenine, thymine, cytosine, and guanine. RNA sequences contain the nitrogen bases adenine, uracil, cytosine, and guanine. If the sequence contains thymine it is a DNA sequence if it contains uracil it is an RNA sequence.
Firstly, DNA is transcripted to mRNA, which is then translated by ribosomes into your polypeptide. Each set of 3 bases on the mRNA (codon) codes for a particular amino acid. However, there can be up to four codons, coding for a single amino acid. ie GCU, GCC, GCA and GCG all code for Alanine. Therefore, if you know the amino acid sequence, you can work backwards to mRNA and then to DNA, but you wouldn't be very accurate as you'd need to guess the codons.
I have just done it. I would like to know what will happen from now on...
I Believe the answer is sequence of nitrogen bases. 70 Year old woman in 5th Grade , i think i know this.
The HIV virus is an RNA virus, so you know the sequence AUCUU is the RNA sequence. (You also know it is RNA because it contains uracil.) HIV is a retrovirus, so its RNA will be transcribed to DNA by the enzyme reverse transcriptase and then inserted into the host's genome. The RNA sequence of AUCUU would be transcribed to TAGTT.
Well, we would have to know how many % of the coding sequence would be exons and introns, but let's ignore this and assume 100% of the sequence are exons;129 aminoacids = 129 codons = 129*3 nucleotides = 387 nucleotides.10 pairs of bases = 3,4 nm;387/10 = 38,738,7 * 3,4 = 131,58 nm.
DNA sequences contain the nitrogen bases adenine, thymine, cytosine, and guanine. RNA sequences contain the nitrogen bases adenine, uracil, cytosine, and guanine. If the sequence contains thymine it is a DNA sequence if it contains uracil it is an RNA sequence.
Firstly, DNA is transcripted to mRNA, which is then translated by ribosomes into your polypeptide. Each set of 3 bases on the mRNA (codon) codes for a particular amino acid. However, there can be up to four codons, coding for a single amino acid. ie GCU, GCC, GCA and GCG all code for Alanine. Therefore, if you know the amino acid sequence, you can work backwards to mRNA and then to DNA, but you wouldn't be very accurate as you'd need to guess the codons.
This is done by and through the use of The Genetic Code.This is actually only partially possible because of the Situation that demands the creation of the term 'Wobble Base'.The implementation of The Genetic Code involves - simply - the [sequential][and consequential] string of Triplet Codons, as represented by the Dna sequence of Bases, being transcribed into messenger Rna which then is presented to the [endoplasmically embedded] Ribosomes; where each triplet codon is exactly represented by ONE amino acid.Whereas there are 64 triplet codons that exist, we need to represent only 20 animo acids - hence the wobble bases.
Every three bases on an mRNA molecule is known as a codon. The tRNA molecules have corresponding base pairs called an anticodon that will only pair up with the codons on mRNA. In this way mRNA specifies the amino acid that tRNA brings next in the sequence on the growing peptide chain.
131*3=393 bases might be there on mRNA strand 3 codons of mRNA strand deduce an aminoacid of a protein, so here, mRNA strand bases are being asked.
The bases present, meaning the codons. They also have a start and stop codon to know what order the code starts and stops at.
"STOP"
I have just done it. I would like to know what will happen from now on...
to produce a protein, geneticists must know the sequence of DNA bases that codes for the protein.
I Believe the answer is sequence of nitrogen bases. 70 Year old woman in 5th Grade , i think i know this.