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Used the transformer. SO will be change 40vdc.

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Humm (no pun intended) - a DC transformer, must be something new in the market. A variable potentiometer will allow you to reduce the voltage to the required voltage you need. It will have to be of a higher wattage variety to dissipate the heat that will be generated depending on the wattage of the load at 40 volts.

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12y ago
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12y ago

For an AC supply, you can use a transformer.

For a DC supply, you can use a voltage-divider. In the simplest case, this comprises a pair of resistors, of appropriate value, placed in series with each other, but in parallel with the supply. The load is then connected in parallel with one of the resistors. Basically, the value of each resistor must be such that one resistor has a voltage drop of 48 V across it, and it is across this resistor that the load is connected. The actual calculation to determine the resistance of each resistor is rather more complicated, as you need to take the resistance of the load into account, too -but this is beyond the scope of this answer.

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11y ago

For an AC voltage you would use a 4:1 step-down transformer rated adequately for the necessary power dissipation.

For a DC voltage you would use a solid-state voltage regulator or a two-resistor voltage divider (having a ratio of 3:1) and taking the output voltage from between the two.

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13y ago

A: Just add a 12 volts zener in series. That will get you 60-12 =48 volts Now you have the voltage 48 how much power can someone draw from it? That is the question to be answered

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11y ago

If both voltages must be AC then use a transformer with a 4:1 turn ratio.

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9y ago

There are DC to DC converter units that can do this. How much power do you need (i.e. wattage)?

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12y ago

with an inductor coil

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Q: How can I step down 48 volt DC to 12 volt DC?
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