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Find an equation for the hyperbola with foci and asymptotes?

Updated: 4/28/2022
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JaleelWright

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11y ago

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find the constant difference for a hyperbola with foci f1 (5,0) and f2(5,0) and the point on the hyperbola (1,0).

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11y ago
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Q: Find an equation for the hyperbola with foci and asymptotes?
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Related questions

How many foci does the graph of a hyperbola have?

Two foci's are found on a hyperbola graph.


How many foci does a hyperbola have?

2


How many foci does half of a hyperbola have?

2


How many foci does a graph of a hyperbola have?

2


What is principal axis in hyperbola?

The principal axis of a hyperbola is the straight line joining its two foci.


What shape has two foci's?

An ellipse, a hyperbola.


How many foci does a graph and hyperbola have?

geometry sorry


What happens when you decrease the distance between two foci?

The answer depends on whether they are the foci of an ellipse or a hyperbola.


What is foci of hyperbola?

A half of a hyperbola is defined as the locus of points such that the distance of the point from one fixed point (a focus) and its distance from a fixed line (the directrix) is a constant that is greater than 1 (the eccentricity). By symmetry, a hyperbola has two foci and two directrices.


What is the focus of a hyperbola?

The foci (plural of focus, pronounced foh-sigh) are the two points that define a hyperbola: the figure is defined as the set of all points that is a fixed difference of distances from the two points, or foci.


What is the equation for a hyperbola with transverse axis of length 24 and centered at the origin?

The standard form of the equation of a hyperbola with center at the origin isx2/a2 - y2/b2 = 1 where the transverse axis lies on the x-axis,ory2/a2 - x2/b2 = 1 where the transverse axis lies on the y-axis.The vertices are a units from the center and the foci are c units from the center.For both equations, b2 = c2 - a2. Equivalently, c2 = a2 + b2.Since we know the length of the transverse axis (the distance between the vertices), we can find the value of a (because the center, the origin, lies midway between the vertices and foci).Suppose that the transverse axis of our hyperbola lies on the x-axis.Then, |a| = 24/2 = 12So the equation becomes x2/144 - y2/b2 = 1.To find b we need to know what c is.


Which two fixed points define the shape of a hyperbola?

the foci (2 focal points) and the distance between the vertices.