No,
Only three combinations can beat a Four of a kind
A higher four of a kind (example : KKKK Vs QQQQ)
Four aces being the highest FoK possible.
Any FoK will be beaten by
A straight flush (5 suited card in a row)
The Royal Flush (which is a Ace high Straight Flush) is the unbeatable hand.
yes. ANSWER The ranking of the hands are: High card
Pair
Two pair
Three of a kind
Straight
Flush Full House
Four of a kind
Straight flush
Royal flush
Yes, it does.
when one or more of the cards in the 4 of a kind are from a different deck.
In reality, never.
Four of a kind is much harder to get, so it wins.
nope
no
Three pairs isn't possible. you have to play 5 cards. so you would play the highest two pairs. So yes, a full house would win.
Four of a Kind Straight Flush Royal Flush
No, a flush cannot beat a full house.
Four pairs of electrons. Neon has a full octet.
A full house always beats a flush, unless it is a straight flush or a royal flush.
No
There are no three pairs in poker, it's only three of a kind or your two highest pairs. So the full house would win. I mean just for starters the full house already has three of a kind within it 3 6's which already beats two pair. So the full house is ONE of the strongest hands in poker.
NO the order is (from lowest to highest) 1 pair 2 two pair 3 three of a kind 4 straight 5 flush 6 full house 7 four of a kind 8 straight flush 9 royal flush
3 of a kind Aces can not beat a full house. In this particular case it is most likely that there was a pair and an ace already on the board, making the 3 aces and the pair on the board a higher full house then the other full house.
Yes
Yes.
Full House.