That completely depends on your television, DVD player, whether you're tv is hooked up to your computer.
TVs can play all sorts of things. Most DVD players made in the last 6 years or so can play JPGS if they are burned onto a disc, though there are always limits. The biggest being the size of the image (large files take longer to display). Regardless if it's on DVD the resolution will be no exceed 720pixels by 480pixes, even if the original was 2000 by2000.
Some newer HD TVs (and DVDs or Blue Rays) can take memory cards directly and can thus display higher resolutions.
If you can hook up the TV to a digital camera or camcorder that's probably the most typical way of displaying a JPG.
Just keep in mind that it's really dependent on the media you are using to display in on and with rather than the JPGs themselves.
v = a t a = v / t Bonus: t = v / a
If the true value is t and the calculated or measured value is v then absolute error = |v - t|, the absolute value of (v - t).If v >= t then the absolute value is v - tif v
he explored bisj and jpgs and jks and paki
Well, V=s/tso, V/t = (s/t)/tor V/t = s/t * 1/tso, V/t= s/(t^2). It is equal to acceleration.
T. V. Padma was born in 1969.
S=vt-16t2 solve for v is what I will assume you mean. first pull out the t S=t(v-16t) then devide by t S/t=v-16t Then add 16t to both sides S/t + 16t = v This can also be written as (S+16t2)/t = v
If: v = u+at Then: -u = -v+at or u = v-at (by dividing all terms by -1) a = (v-u)/t t = (v-u)/a
T. V. Bulpin was born in 1918.
V. T. Bhattathiripad died in 1982.
V. T. Bhattathiripad was born in 1896.
V. T. Rajshekar was born in 1932.
V. T. Hamlin died in 1993.