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Yes, but . . .

There were four parties competing for President in 1860. The Republicans and the Democrats were two, but the Southern Democrats and the Constitutional Union party also were in the mix. Lincoln and Douglas represented the Republican and Democratic Parties. John Bell and John Breckinridge were the candidates of the Constitutional Union and the Southern Democratic Parties.

These were not minor candidates. Breckinridge won eleven states (Basically the deep South) and Bell won three (The Southern border states of Virginia, Kentucky and Tennessee.) Douglas, the Democrat in your question, won only one state (Missouri.)

Abraham Lincoln won eighteen States (essentially all of the states outside the South, California and Oregon -- Maryland and Delaware went to Breckinridge.

One way to look at the election; the Democratic Party split into two and there was a third party as well. Adds up to four parties competing for the Presidency in 1860.

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12y ago
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11y ago

Not exactly. The Republican, Abraham Lincoln was contested by the Southern Democrat John C. Breckinridge and Northern Democrat Stephen Douglas and he also was challenged by Constitutional Union candidate John Bell. The most serious opponent was John Breckinridge; Douglas only won 1 state (Missouri) and he and Bell together only won four states.

There were 33 states in the union at that time. Lincoln won 18 states and won 180 electoral votes over the opponents total of 15 states and 123 electoral combined. He received 39.8% of the over all vote.

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Q: Is it true one democrat and one republican competed in the election of 1860?
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Who was the Republican Party candidate for president in the Election of 1860?

Abraham Lincoln was the winning Republican candidate for president in 1860.


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The modern republican party was formed for the 1860 election. Abraham Lincoln was their first presidential candidate. Their main platform was to stop the expansion of slavery to 'The West'


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