The question has been truncated.
I suspect it either should end: "...none of the calculators work," in which case:
for all 3 to be faulty the probability is 1/10 × 1/10 × 1/10 = 1/1000 = 0.001 = 0.1 %
or: "...none of the calculators are faulty," in which case:
for all 3 to not be faulty the probability = 9/10 × 9/10 × 9/10 = 729/1000 = 0.729 = 72.9 %
Unfortunately, the browser used by Answers.com for posting questions limits the size of the question. In this case it is not clear whether you are asking about "none of the calculators work" or "none of them are defective"!
Prob(None work) = 0.001
Prob(None defective) = 0.729)
1/15 or about 0.07
It is 5C1*(1/10)1*(9/10)4 = 0.3281
Defective numbers are when all the factors of a number add up to be smaller than the number.Ex.:39 1+3+13=17 17<39 39 is defective
If it is a linear relationship then it is (32/850)*22000 = 828.23 or simply 829
Unit rate of defective products = number of defectives/Total = 30 / (18000 + 30) = 30/18030 = 0.00166 (to 5 dp)
100%
1-.015 = .985
Homework question? This is actually not a question of probability: if 95% of the parts are non-defective, then 0.95 * 500 = 475 parts are non-defective. So there is zero (0) probability that fewer than 472 parts are non-defective. The question is different when any part has a probability (chance) of 95% of being non-defective. This is a so called Binomial distribution. Google knows the answer.
The mean is 0.1
It is 0.8
If the probability of a single plug being defective is p then the required probability is 1 - (1- p)4 = 4p - 6p2 + 4p3 - p4
8 were defective while (75-8=67) weren't. So the estimated probability that a flyer won't be defective is 67/75
Just divide 24 (the number of defective batteries) by 60 (the total number).
1/15 or about 0.07
i dont get it? --- The probability that the first iPod you select is not defective is 16/20. If you selected a non-defective iPod the first time, there are now 15 non-defective iPods out of 19 remaining. So, the odds that the second you selected is non-defective is 15/19. By similar reasoning, the probability that the third is non-defective (given that the first two weren't defective) is 14/18, and for the fourth iPod, it is 13/17. So the probability that none of the four iPods you selected are defective is: (16/20)*(15/19)*(14/18)*(13/17)=364/969, or approximately 37.6%
idon't know
in a certain statistical experiment, the probability of a success is 0.20. if the experiment is conducted 80 time, what is the probability of getting 20 successes or more?