To use an adapter of this sort, its rated voltage must match the rated voltage of the appliance, and its rated current must exceed that of the appliance. So, in your example, the rated voltage is too high to be used with your appliance.
Yes, no problem whatsoever. The adaptor will only be operating at 50% of it capacity.
You just need the voltage and the current. Watts = Amps x Volts.
Basically if you know the Voltage supply and the power used by an appliance then you use the formula for power which is Power = Volts x Amps. Rearrange so Amps (current) = Power / Volts If power was 2400 Watts and Volts was 240 the Current would be 2400 / 240 = 10 Amps
Let R be the resistance, V the voltage, and I the current R = V / I R = 120 / 24 R = 5 ohm
To convert watts into amperes you divide the circuit voltage into the watts. Amps = Watts/Volts. <<>> Converting Watts to Amps The conversion of Watts to Amps is governed by the equation Amps = Watts/Volts For example 12 watts/12 volts = 1 amp Converting Amps to Watts The conversion of Amps to Watts is governed by the equation Watts = Amps x Volts For example 1 amp * 110 volts = 110 watts Converting Watts to Volts The conversion of Watts to Volts is governed by the equation Volts = Watts/Amps For example 100 watts/10 amps = 10 volts Converting Volts to Watts The conversion of Volts to Watts is governed by the equation Watts = Amps x Volts For example 1.5 amps * 12 volts = 18 watts Converting Volts to Amps at fixed wattage The conversion of Volts to Amps is governed by the equations Amps = Watts/Volts For example 120 watts/110 volts = 1.09 amps Converting Amps to Volts at fixed wattage The conversion of Amps to Volts is governed by the equation Volts = Watts/Amps For Example, 48 watts / 12 Amps = 4 Volts Explanation Amps are how many electrons flow past a certain point per second. Volts is a measure of how much force that each electron is under. Think of water in a hose. A gallon a minute (think amps) just dribbles out if it is under low pressure (think low voltage). But if you restrict the end of the hose, letting the pressure build up, the water can have more power (like watts), even though it is still only one gallon a minute. In fact the power can grow enormous as the pressure builds, to the point that a water knife can cut a sheet of glass. In the same manner as the voltage is increased a small amount of current can turn into a lot of watts.
The equation that you are looking for is Watts = Amps x Volts. Power is consumed at that rate over a time constant. You are billed by the electrical utility company by the kWh. 1000 watts are equal to 1 kW.
No. Your power supply must be able to supply rated voltage (12 volts) and rated current (3 amps).
An adapter can be used. Make sure that the adapter that you use is of a capacity that it can produce the amperage that your appliance needs. An adapter too small will burn itself open and will be of no use to anyone. Remember; Watts = Amps x Volts.
When you multiply amps x volts the product is watts. Using this formula W = Amps x Volts should give you your answer.
Amps (current) times volts = watts. so watts divided by volts = current (Amps). i.e.- 0.5 Amps.
12 volts.
difference is 2.7 amperes in numbers will be 12 volts 3 amps and the other will be 12 volts .3 amps
Power = volts times amps, so an appliance drawing 10 amps at a line voltage of 110 volts is consuming 1,100 watts. Keep in mind, however, that in a non purely resistive load, the phase angle of amps to volts might not be zero degrees, so the calculation becomes more complex, and depends on power factor, or phase angle.
The terminal strip's rating is 15 amps at 600 volts. It does not matter what the voltage is up to 600 volts, the maximum amperage allowed on the strip is 15 amps. It could be 15 amps at 12 volts or 15 amps at 600 volts or any voltage in between.
Yes, an appliance that is 115 volts 15 amps can be plugged into a normal household electrical outlet in the Untied States of America, also available in Canada. LOL
The watt is the unit of power. For electricity, watts = volts x amps.
it is 795 divided by 120. <<>> The formula you are looking for is I = W/E, Amps = Watts/Volts.
A # 14 copper conductor will be fine to carry 8 amps at 120 volts. This size conductor is rated at 15 amps.