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Can the angle bisector of a triangle also be the perpendicular bisector?
Wiki User
∙ 13y ago
Yes. The bisector of one angle of a triangle is the perpendicular bisector of the
opposite side if the bisected angle is the vertex angle of an isosceles triangle,
or any angle of an equilateral triangle.
Wiki User
∙ 13y ago
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Is this True or false the angle bisector of the vertex angle of an isosceles triangle is also the perpendicular bisector of the base?
True
Which types of triangles must always have at least one angle bisector that is also a perpendicular bisector?
iscoceles triangle! =)
Is the angle bisector also the median in an equilateral triangle?
No. The angle bisector is a line. Where the three lines meet is the median. In an equilateral triangle the INTERSECTION of the angle bisectors is the median.
Why is the angle bisector of an isosceles triangle also Euler's line?
the circumcenter, orthocenter, and centriod, when connected together i Euler's line. the angle bisector of the non base angle is the same thing.
When a ray splits an angle in half what is it called?
a bisector splits an angle into to congruent angles(also called an angle bisector)
What triangle must always have at least one angle bisector that is also a perpendicular bisector?
any isosceles triangle
Is this True or false the angle bisector of the vertex angle of an isosceles triangle is also the perpendicular bisector of the base?
True
For what kinds of triangles can the perpendicular bisector of a side also be an angle bisector of the angle opposite the side?
Every isosceles or equilateral triangle.
Which types of triangles must always have at least one angle bisector that is also a perpendicular bisector?
iscoceles triangle! =)
Can an altitude be a perpendicular bisector?
Yes - the altitude of an equilateral triangle is perpendicular to the side chosen as the base and bisects that side and the opposite angle. Also, the altitude of an isosceles triangle when measured from the third side (the side that is not equal to the other two sides) is a perpendicular bisector of the base and also bisects the opposite angle.
What are 2 properties of an isosceles triangle?
-- An isosceles triangle has two equal sides. -- An isosceles triangle has two equal angles. -- An isosceles triangle has two equal interior-angle bisectors. -- The bisector of the vertex angle of an isosceles triangle is also the perpendicular bisector of the triangle's base.
Is the altitude of an isosceles triangle the angle bisector of the vertex?
Yes, provided that the base is not one of the 2 equal sides. And it's also the perpendicular bisector of the base.
Is the three perpendicular bisector of a triangle intersect at a point in the exterior of the triangle true or false?
The three ANGLE bisectors of a triangle also bisect the sides, and intersect at a point INSIDE the triangle. The angle bisectors are not necessarily perpendicular to them. The perpendicular bisectors of the sides can intersect in a point either inside or outside the triangle, depending on the shape of the triangle.
Is the angle bisector also the median in an equilateral triangle?
No. The angle bisector is a line. Where the three lines meet is the median. In an equilateral triangle the INTERSECTION of the angle bisectors is the median.
What triangle has an altitude which is also a median and angle bisector?
An isosceles or an equilateral triangle perhaps?
What is the proof that equiangular triangle is also called equilateral triangle?
Label the triangle ABC. Draw the bisector of angle A to meet BC at D. Then in triangles ABD and ACD, angle ABD = angle ACD (equiangular triangle) angle BAD = angle CAD (AD is angle bisector) so angle ADB = angle ACD (third angle of triangles). Also AD is common. So, by ASA, triangle ABD is congruent to triangle ACD and therefore AB = AC. By drawing the bisector of angle B, it can be shown that AB = BC. Therefore, AB = BC = AC ie the triangle is equilateral.
What bisects an angle?
The Angle Bisector Theorem states that given triangle and angle bisector AD, where D is on side BC, then . Likewise, the converse is also true. Not sure if this is what you want?
