the volume of the box would be 4x^3-42x^2+80x since a volume wasn't given to find 'x' or a set 'x' wasn't given, that is the equation you would use
If you take a square, side x, from each corner then the base of your box becomes (20-2x) by (6-2x). The height is then x. Draw a picture if it will help you visualize. Also, please feel free to do your own homework. We know school is back in session, but please do not use Wikianswers to cheat on assignments. kthxbai
I get 204 There are 64 1x1 squares; 49 2x2 squares; 36 3x3 squares; 25 4x4 squares; 16 5x5 squares; 9 6x6 squares, 4 7x7 squares and 1 8x8 square.
x is the number of squares to the right or left a point is from zero y is the number of squares up or down the point is from zero and ordered pair is written (x,y)
squares,rectangles,regular pentagons
A cube has six faces which are all squares. A cuboid has 2, 4 or 6 rectangular faces.
It is 4x^3 - 13x^2 + 30x cubic inches.
No they are not, they have corners.
Rectangles and squares both have 4 corners.
Yes squares ALWAYS have corners but they can be a sharp point or a very slightly rounded edge. Hope this helps!!
Each square has four corners, and each triangle has three corners. 5 squares X 4 corners/square = 20 corners 3 triangles X 3 corners/triangle = 9 corners 20 + 9 = 29 corners total.
it is a triangle with circles at the corners, and squares in the middle of the corners. The squares have numbers in them, and you have to put numbers in the circles. However, the numbers in the circles have to add up to the number of the square between them. Simple, right?
Colorado and wyoming
If you take a square, side x, from each corner then the base of your box becomes (20-2x) by (6-2x). The height is then x. Draw a picture if it will help you visualize. Also, please feel free to do your own homework. We know school is back in session, but please do not use Wikianswers to cheat on assignments. kthxbai
Any rectangle (including squares).
well that's a dumb question figure it out! but, its 12
quadrilaterals like squares and rectangles and parallelograms and a rhombus
You really should consider trying this yourself before reading the answer, and you should understand the answer, otherwise you will not learn the lesson. Read each step, and do not proceed unless you understand it.To maximize the volume of an open box made from a sheet of material 8 x 3, by cutting equal squares of side x from the corners and folding up the sides, first draw the box...The box is 8-2x by 3-2x by x. Try again to draw it...The volume of the box is (8-2x)(3-2x)x. Can you see the solution?Simplify the volume. It is 4x3 - 22x2 + 24x. Can you see the solution?Differentiate. This is a simple polynomial. Can you see the solution?The deriviative is dy/dx = 12x2 - 44x + 24. Can you see the solution?The maximum volume occurs when the deriviative is zero. Can you see the solution?Solve for 12x2 - 44x + 24 = 0. How about the quadratic equation? Last chance to solve it yourself.There are two roots of x: 3, and 2/3. 3, however, is not valid because you can not cut a square larger than 1.5 out of the original side of 3, so the answer is 2/3.