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Find capacitance:

C = Er * Eo * A / d

C = (1.0005898) * (8.854×10−12)* (1meter squared) / 2 x 10^-6

C = 4.42 micro farads

To determine charge Q:

Q = C*V = 4.42 x 10^-6 * 10 volts = 4.42 x 10^-5 coulumbs.

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Q: A parallel plate capacitor with each plate having area of 1m2 and you separate the plates by 2 µm what is the value of the capacitance how much charge will the capacitor store connected to a 10V batt?
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