A5uf capacitor has 5*10-4 coulombs of charge stored on its plates
basically a capacitor will charge to the input DC level however it will mathematically never happen since capacitors charge at a certain rate the voltage drop across a capacitor will follow the R C time constant or 63% of the applied voltage for a unit time.AnswerIn the case of an a.c. supply, yes, there will be a voltage drop across a capacitor. In the case of an 'ideal' capacitor, this will be the product of the load current and the capacitive reactance of the capacitor.
(a) what is the total capacitance of this arrangement (B) the charge stored on each capacitor (C) the voltage across the 50 micro farad capacitor and the energy stored in it. 20v and 20+30+50 micro farad
Yes, voltage matters when charging a capacitor. Capacitor charge rate is proportional to current and inversely proportional to capacitance. dv/dt = i/c So, voltage matters in terms of charge rate, if you are simply using a resistor to limit the current flow, because a larger voltage will attempt to charge faster, and sometimes there is a limit on the current through a capacitor. There is also a limit on voltage across a capacitor, so a larger voltage could potentially damage the capacitor.
Voltage and current are two different things. Voltage is potential energy per charge, in joules per coulomb, while current is charge transfer rate, in coulombs per second. Its that same as saying that a battery has voltage but no current, because there is no load. Well, a capacitor resists a change in voltage by requiring a current to change the voltage. Once that voltage is achieved, there is infinite resistance to the voltage, and thus no current.
A capacitor can charge to its' maximum OR the voltage applied to it, whichever is LESS.
In order to double the voltage across a capacitor, you need to stuff twice as much charge into it.
You charge a capacitor by placing DC voltage across its terminal leads. Make sure when using a polarized capacitor to place positive voltage across the positive lead (the longer lead) and negative voltage across the negative lead. Also make sure that the voltage you charge the capacitor to doesn't exceeds its voltage rating.
9200 volts my 1000 uF capacitor only holds 10 volts
basically a capacitor will charge to the input DC level however it will mathematically never happen since capacitors charge at a certain rate the voltage drop across a capacitor will follow the R C time constant or 63% of the applied voltage for a unit time.AnswerIn the case of an a.c. supply, yes, there will be a voltage drop across a capacitor. In the case of an 'ideal' capacitor, this will be the product of the load current and the capacitive reactance of the capacitor.
(a) what is the total capacitance of this arrangement (B) the charge stored on each capacitor (C) the voltage across the 50 micro farad capacitor and the energy stored in it. 20v and 20+30+50 micro farad
Yes, voltage matters when charging a capacitor. Capacitor charge rate is proportional to current and inversely proportional to capacitance. dv/dt = i/c So, voltage matters in terms of charge rate, if you are simply using a resistor to limit the current flow, because a larger voltage will attempt to charge faster, and sometimes there is a limit on the current through a capacitor. There is also a limit on voltage across a capacitor, so a larger voltage could potentially damage the capacitor.
Battery, resistor, and capacitor are connected in series. E = voltage of the battery, volts R = resistance of the resistor, ohms C = capacitance of the capacitor, farads T = time since the circuit was completed, seconds I = current in the circuit, amperes Vc = voltage across the capacitor, volts Q = charge on the capacitor, coulombs e = base of natural logs = approx 2.7183 At any time 'T' after everything is connected up, Vc = E x (1 - e-T/RC) volts I = (E/R) e-T/RC amperes or I = (E - Vc) / R Q = 1/2 C Vc2 coulombs or Q = 1/2 C E2 (1 - e-T/RC )2 coulombs See ? Nothing to it.
Voltage and current are two different things. Voltage is potential energy per charge, in joules per coulomb, while current is charge transfer rate, in coulombs per second. Its that same as saying that a battery has voltage but no current, because there is no load. Well, a capacitor resists a change in voltage by requiring a current to change the voltage. Once that voltage is achieved, there is infinite resistance to the voltage, and thus no current.
A capacitor can charge to its' maximum OR the voltage applied to it, whichever is LESS.
In an electronic circuit a capacitor can be used to block direct current. In general a capacitor stores electric charge. The charge in a capacitor is the voltage times the capacitance and that is also equal to the charging current times the time (all quantities in SI units - seconds, volts, amps, coulombs, farads)
calulate the voltage of a battery that provides 20 joules of energy to every 5 coulombs of charge
capacitor blocks DC, after it finishes charging. Actually, it resists any CHANGE to DC (ie ac), after it has finished charging. IRT the actual question, current will always flow, as long as there is a closed circuit.