answersLogoWhite

0


Best Answer

Potential Energy is given by the fourmulai PE=MGH where M=mass in kilos, G=the force of gravity in Netwons (9.8N) and H=height in meters. So 50*9.8*10=4900joules. A Watt is a unit of power that =1 joule per second. So 4900 joules divided by 5 seconds = 980 Watts, not allowing for losses due to friction etc.

User Avatar

Wiki User

15y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

12y ago

Work = (force) x (distance)

The minimum force required to lift the crate is equal to its weight.

Work = (weight) x (distance) = (mass x gravity) x (Height) = (50 x 9.807) x (10) = 4,903.5 joules

This answer is:
User Avatar

User Avatar

Wiki User

9y ago

The crate's potential energy is 4,900 joules.

This answer is:
User Avatar

User Avatar

Wiki User

12y ago

And what is the question?

And what is the question?

And what is the question?

And what is the question?

This answer is:
User Avatar

User Avatar

Wiki User

13y ago

Work=F x d

Therefore; Work= 20 x 10 = 200 Joules

This answer is:
User Avatar

User Avatar

Wiki User

13y ago

If that task is done on earth, then it requires 4,900 hundred joules of energy.

This answer is:
User Avatar

User Avatar

Wiki User

9y ago

The crate's PE is 4900 joules.

This answer is:
User Avatar

User Avatar

Wiki User

13y ago

9800 or 9,800

This answer is:
User Avatar

User Avatar

Wiki User

12y ago

And what is the question?

This answer is:
User Avatar

User Avatar

Wiki User

11y ago

735 J

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How much work is done in lifting a 50kg crate a vertical distance of 10 meters?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Physics

If a worker pushes horizontally on a large crate with a force of 298 newtons and the crate moved 6.5 meters how much work do he do?

Work = force x distance = Newtons x meters = 1937 Joules.


How much work is performed when a 25-kilogram crate is pushed 5 meters with a force of 15 newtons?

Work = (force) x (distance) = (15) x (5) = 75 joules.The mass of the crate is irrelevant.


If it took 5 seconds to lift the crate using a machine what was the power rating of the machine?

We have no way of knowing what power the machine was rated for, but with the information given in the question, we can calculate the power it delivered during the crate-lift: It was (1.96) x (mass of the crate in kilograms) x (distance the crate was lifted in meters) watts.


How much work is performed when 100 kg crate is pushed 30 meters with a force of 40 newtons?

Multiply the force by the distance. The mass is irrelevant for this problem.


A forklift picks up a crate using 400 N It moves the crate 20 meters in 50 seconds How much power is used?

From the question, it's hard to tell whether the 20 meters is the vertical lift, or a horizontal transfer that occurs after the lift.If the 20 meters is the vertical lift (performed by a very large fork-lift in a shop with a very high ceiling):Energy = work = 400 N times 20 m = 8,000 Newton-meters = 8,000 joules8,000 joules in 50 seconds = 8,000 / 50 = 160 joules per second = 160 watts = about 0.214 horsepower.If the 20 meters is a horizontal ride after the lift is complete, then that part of the move consumes nominally no energy or power. No force is required to move an object perpendicular to the force of gravity. Whatever force is applied initially, to get the crate moving, is returned at the end of the 20 meters, when reverse force must be applied to the crate in order to make it stop moving.

Related questions

What is the potential energy of a crate lifted with a force of 100 newtons a vertical distance of 2 meters?

Force x distance = 100 x 2 = 200 newton-meters = 200 joules.


If a worker pushes horizontally on a large crate with a force of 298 newtons and the crate moved 6.5 meters how much work do he do?

Work = force x distance = Newtons x meters = 1937 Joules.


How much work is performed when a 25-kilogram crate is pushed 5 meters with a force of 15 newtons?

Work = (force) x (distance) = (15) x (5) = 75 joules.The mass of the crate is irrelevant.


If it took 5 seconds to lift the crate using a machine what was the power rating of the machine?

We have no way of knowing what power the machine was rated for, but with the information given in the question, we can calculate the power it delivered during the crate-lift: It was (1.96) x (mass of the crate in kilograms) x (distance the crate was lifted in meters) watts.


How do i lift the crate in misa's pieces on the JONAS video game?

You don't actually lift the crate. You drag it. To do so you touch the crate with your stylus and without lifting the stylus drag your Jonas to the spot you want to take the crate to and release.


How much work is performed when 100 kg crate is pushed 30 meters with a force of 40 newtons?

Multiply the force by the distance. The mass is irrelevant for this problem.


Which jobs would a pulley be BEST suited for?

lifting a large crate tied with rope into a ship


A forklift picks up a crate using 400 N It moves the crate 20 meters in 50 seconds How much power is used?

From the question, it's hard to tell whether the 20 meters is the vertical lift, or a horizontal transfer that occurs after the lift.If the 20 meters is the vertical lift (performed by a very large fork-lift in a shop with a very high ceiling):Energy = work = 400 N times 20 m = 8,000 Newton-meters = 8,000 joules8,000 joules in 50 seconds = 8,000 / 50 = 160 joules per second = 160 watts = about 0.214 horsepower.If the 20 meters is a horizontal ride after the lift is complete, then that part of the move consumes nominally no energy or power. No force is required to move an object perpendicular to the force of gravity. Whatever force is applied initially, to get the crate moving, is returned at the end of the 20 meters, when reverse force must be applied to the crate in order to make it stop moving.


How much work is done if you push a 100N crate with friction of 70N across a 10m floor?

Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.


How much work in joules is performed when a force of 800.0 N is exerted while pushing a crate across a level floor for a distance of 1.5 meters?

We must assume that the force pushes parallel to the floor.Work = (force) x (distance) = (800) x (1.5) = 1,200 newton-meters = 1,200 joules


A simple machine such as a pulley is used to make work easier Erin used 50 newtons of force to lift a crate 3 meters She then tied the crate to a pulley and used the pulley to lift the crate again?

yes


A simple machine such as a pulley is used to make work easier. Erin used 50 newtons of force to lift a crate 3 meters. She then tied the crate to a pulley and used the pulley to lift the crate again.?

yes