Reactants: 30 g (NH4)2Cr2O7, 20 g MgSO4 30 g (NH4)2Cr2O7 / 252.07 g/mol = 0.119 mol 20 g MgSO4 / 120.41 g/mol = 0.166 mol Since they react in a 1:1 ratio to form magnesium dichromate and ammonium sulfate, ammonium dichromate is the limiting reagent (only 0.119 mol of MgSO4 is needed to react with all the (NH4)2Cr2O7).
the limiting factor varies between the magnesium and hydrochloric acid as there needs to be enough hydrogen for every magnesium..
This is the amount of magnesium.
The limiting reagent is sodium hydroxide.
nitrogen is often (though not always) the limiting factor in plant growth, and since both the ammonium (NH3) and the nitrate (NO3) both contain nitrogen (N) and plants can absorb both these molecules, it can inhance plant growth.
For plants, there are three main limiting factors that affect the rate of photosynthesis. >Light and its intensity >Carbon dioxide concentration >Temperature As for nutrients .. Magnesium is up taken by the plants roots through osmosis in the root hairs.. to help in production of chlorophyll.
2Mg + O2 -----> 2MgO So two moles of magnesium oxide are formed if x moles of magnesium are allowed to react with only 1 mole of oxygen molecules. The oxygen has become the limiting ingredient.
magnesium + chlorine --> magnesium chloride Mg (s) + Cl2 (g) --> MgCl2 (s) 5.60 g Mg x 1 mol Mg x 1 mol MgCl2 x 95.21 g MgCl2 = 21.9 g MgCl2 ..................24.31 g Mg. 1 mol Mg........ 1 mol MgCl2
Mg2+(s) + 2HNO3(l)= Mg(NO3)2(aq) + H2(g) since the only mole value given is 8 I must assume this is the limiting reactant. Because of the 2:1 ratio of Nitric acid to Magnesium Nitrate, meaning there must be 2 moles Nitric acid for every 1 mole Magnesium Nitrate formed, 4 moles of Magnesium nitrate will be formed.
Limiting factor
The term "limiting" is used because the limiting reactant limits the amount of product produced.
The formula of magnesium sulphide is MgS, showing that a formula unit has one atom of each element. The gram atomic mass of magnesium is 24.305 and that of sulphur is 32.06. Therefore, when magnesium and sulphur are present in equal amounts by mass, sulphur is the limiting reactant. 1.0/32.06 or 0.031 moles of sulphur atoms are present. Therefore, the maximum amount of MgS that can result from reaction is 0.031 formula units of MgS. The gram formula mass of MgS is 56.365, so that 0.031 formula units of MgS will have a mass of 1.7 grams, to the justified number of significant digits.
MgCl2(aq) + 2KOH(aq) --> Mg(OH)2(s) + 2KCl(aq)It is the molar ratio in the equation. Every mole of magnesium chloride requires 2 moles of potassium hydroxide. Thus 3 moles would need 6 moles of alkali for complete reaction. We don't have that much, so potassium hydroxide is the limiting reactant and we can only use 2 moles of the magnesium chloride and produce 2 moles of magnesium hydroxide.